#include<stdio.h>
#include<conio.h>
void main()
{
int n,c,s=0,m,i,f=1;
clrscr();
printf("\n ENTER A VALUE : ");
scanf("%d",&n);
m=n;
while(n>o)
{
c=n%10;
for(i=0;i<c;i++)
f=f*i;
s=s+f;
f=1;
n=n/10;
}
if(s==m)
printf("\n THE ENTERED NUMBER IS PETERSON
NUMBER.");
else
printf("\n THE ENTERED NUMBER IS NOT A
PETERSON NUMBER.");
getch();
}
Saturday, June 4, 2011
C Program to check whether a number is a Peterson Number or not
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i think the initialization in for loop is wrong. f will always be zero. right thin is for(i=1;i<=n;i++)
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