I hope my programs help you a bit. .............(Pradeep)
can you please expain the solution
a[i] == *(a+i) a[i][j] == *(*(a+i)+j) a[i][j][k] == *(*(*(a+i)+j)+k) a[i][j][k][l] == *(*(*(*(a+i)+j)+k)+l)
Yup! thats right! thanx Sachin!
can you please expain the solution
ReplyDeletea[i] == *(a+i)
ReplyDeletea[i][j] == *(*(a+i)+j)
a[i][j][k] == *(*(*(a+i)+j)+k)
a[i][j][k][l] == *(*(*(*(a+i)+j)+k)+l)
Yup! thats right! thanx Sachin!
Delete