I hope my programs help you a bit. .............(Pradeep)

can you please expain the solution

a[i] == *(a+i) a[i][j] == *(*(a+i)+j) a[i][j][k] == *(*(*(a+i)+j)+k) a[i][j][k][l] == *(*(*(*(a+i)+j)+k)+l)

Yup! thats right! thanx Sachin!

can you please expain the solution

ReplyDeletea[i] == *(a+i)

ReplyDeletea[i][j] == *(*(a+i)+j)

a[i][j][k] == *(*(*(a+i)+j)+k)

a[i][j][k][l] == *(*(*(*(a+i)+j)+k)+l)

Yup! thats right! thanx Sachin!

Delete